Answer:
d = 4.9 m
Explanation:
It is mentioned that a stone is dropped from a certain height. It is required to find the distance covered by it in one second.
The initial speed of the stone is equal to 0 as it was at rest. Let d is the distance covered by the stone.
Using second equation of motion :
[tex]d=ut+\dfrac{1}{2}at^2[/tex]
Put u = 0 and a = g
[tex]d=\dfrac{1}{2}gt^2\\\\d=\dfrac{1}{2}\times 9.8\times 1^2\\\\d=4.9\ m[/tex]
So, the distance covered by it in one second is 4.9 m.
