Answer:
[tex](C)2\sqrt{7}[/tex]
Step-by-step explanation:
Given a circle Q represented by the equation:
[tex](x -11)^2 + (y + 15)^2 = 7.[/tex]
Comparing with the standard form of the equation of a circle center (h,k) of radius r:
[tex](x-h)^2+(y-k)^2=r^2[/tex]
We have:
[tex]r^2=7[/tex]
We take the square root to obtain the radius, r of the circle.
[tex]r=\sqrt{7}[/tex]
Since segment KL is a diameter of circle Q; and
Diameter =Radius X 2
Therefore:
[tex]|KL|=2\sqrt{7}[/tex]
