Answer:
[tex]\large \boxed{\$6307.63}[/tex]
Step-by-step explanation:
We can use the formula for interest compounded continuously.
[tex]\begin{array}{rcl}A & = & Pe^{rt}\\& = & 6000e^{0.025 \times 2}\\& = &6000e^{0.050}\\& = & 6000\times 1.05127\\& = &\mathbf{\$6307.63}\\\end{array}\\\text{The balance on the account is $\large \boxed{\mathbf{\$6307.63}}$}[/tex]
