Respuesta :

isaacoranseola

Answer:

176984.38J

Explanation:

E = mC∆T

Where E is the energy in joules

M is the mass of water

C is the specific heat capacity of water =4.184J/g°C

It is known that it will take 4.184J of energy to change the temperature of water by one degree Celsius.

∆T = 98.6°c - 5.4°c

= 93.2°c

∆H = 454.3g × 4.18J/g°C × 93.2°c

= 176984.3768

176984.38J

samueladesida43

The joules of energy required to heat 454.3g of water from 5.4°C to 98.6°C is 177153.628J.

HOW TO CALCULATE ENERGY:

  • The energy required to heat a substance can be calculated by using the following formula:

  • Q = m × c × ∆T

Where;

  1. Q = amount of heat absorbed or released (J)
  2. m = mass of substance (g)
  3. c = specific heat capacity (J/g°C)
  4. ∆T = change in temperature (°C)

  • According to this question, 454.3g of water increased from 5.4°C to 98.6°C. The energy can be calculated as follows:

  • Q = 454.3 × 4.184 × (98.6 - 5.4)

  • Q = 1900.79 × 93.2

  • Q = 177153.628J

  • Therefore, joules of energy required to heat 454.3g of water from 5.4°C to 98.6°C is 177153.628J

Learn more at: https://brainly.com/question/11194034?referrer=searchResults

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