Answer:
The charge on each particle is [tex]q =2.832 *10^{-11} C[/tex]
Explanation:
From he question we are told that
The distance of separation between particles is [tex]d = 3.8 cm = 0.038m[/tex]
The force exerted by on of the charged particle on the other charge particles is [tex]F = 5 *10^{-9}[/tex]
Generally the between these charge particle can be mathematically represented as
[tex]F = \frac{k q_1 q_2 }{d^2}[/tex]
Where k is the colombe constant with a value of [tex]k = 9*10^9\ kg \dot m^3 \cdot s^{-4} A^{-2}[/tex]
Since the charge are identical
[tex]q_1 = q_2 = q[/tex]
So the equation becomes
[tex]F = \frac{k q^2 }{d^2}[/tex]
Making q the subject of the formula
[tex]q =\sqrt{ \frac{F * d^2 }{k}}[/tex]
Substituting values
[tex]q =\sqrt{ \frac{5*10^{- 9} * 0.038^2 }{9*10^9}}[/tex]
[tex]q =2.832 *10^{-11} C[/tex]
