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Express the equilibrium constant for the following reaction. 3 CH3Cl(g) + 3/2 Cl2(g) ⇔ 3 CH2Cl2(g) + 3/2 H2(g) Express the equilibrium constant for the following reaction. 3 CH3Cl(g) + 3/2 Cl2(g) ⇔ 3 CH2Cl2(g) + 3/2 H2(g) K = [CH3Cl][Cl2]5[CH2Cl2][H2]5 K = [CH3Cl]3[Cl2]3/2[CH2Cl2]3[H2]3/2 K = [CH3Cl][Cl2][CH2Cl2][H2] K = [CH2Cl2][H2]3[CH3Cl][Cl2]5 K = [CH2Cl2]3[H2]3/2[CH3Cl]3[Cl2]3/2

Respuesta :

Eduard22sly

Answer:

K = [CH2Cl2]^3 [H2]^3/2 /[CH3Cl]^3 [Cl2]^3/2

Explanation:

Step 1:

We'll begin by writing the balanced equation the reaction. This is given below:

3CH3Cl(g) + 3/2Cl2(g) <=> 3CH2Cl2(g) + 3/2H2(g)

Step 2:

Writing an expression of the equilibrium constant. This is illustrated below:

The equilibrium constant is simply the ratio of the concentration of the products to that of the reactants. The equilibrium expression for the equilibrium constant for the above reaction is given below:

K = [CH2Cl2]^3 [H2]^3/2 /[CH3Cl]^3 [Cl2]^3/2

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