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An equilibrium mixture of CO, O2 and CO2 at a certain temperature contains 0.0010 M CO2 and 0.0015 M O2. At this temperature, Kc equals 1.4 × 102 for the reaction: 2 CO(g) + O2(g) ⇌ 2 CO2(g). What is the equilibrium concentration of CO? An equilibrium mixture of CO, O2 and CO2 at a certain temperature contains 0.0010 M CO2 and 0.0015 M O2. At this temperature, Kc equals 1.4 × 102 for the reaction: 2 CO(g) + O2(g) ⇌ 2 CO2(g). What is the equilibrium concentration of CO? 3.1 × 10-1 M 4.8 × 10-6 M 2.2 × 10-3 M 1.9 × 10 7 M 9.3 × 10-2 M

Respuesta :

Answer:

Equilibrium concentration of CO is [tex]2.2\times 10^{-3}[/tex] M.

Explanation:

Chemical Reaction: [tex]2CO(g)+O_{2}(g)\rightleftharpoons 2CO_{2}(g)[/tex]

Equilibrium constant for this reaction in terms of concentration is represented as:                        [tex]K_{c}=\frac{[CO_{2}]^{2}}{[CO]^{2}[O_{2}]}[/tex]

where, [tex][CO_{2}][/tex], [tex][CO][/tex] and [tex][O_{2}][/tex] represent equilibrium concentration of [tex]CO_{2}[/tex], CO and [tex]O_{2}[/tex] respectively.

Here, [tex][CO_{2}][/tex] = 0.0010 M , [tex][O_{2}][/tex] = 0.0015 M and [tex]K_{c}=1.4\times 10^{2}[/tex]

So, [tex][CO]=\sqrt{\frac{[CO_{2}]^{2}}{K_{c}.[O_{2}]}}[/tex] M  = [tex]\sqrt{\frac{(0.0010)^{2}}{(1.4\times 10^{2})\times (0.0015)}}[/tex] M = [tex]2.2\times 10^{-3}[/tex] M

So, equilibrium concentration of CO is [tex]2.2\times 10^{-3}[/tex] M.

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