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25.0 cm3 of a solution of sodium hydroxide required 18.8 cm3 of 0.0500 mol/dm3 H2SO4

H2SO4+2NaOH—> Na2SO4+ 2H2O

1) find the concentration of the sodium hydroxide solution in mol/dm-3

2) find the concentration of sodium hydroxide solution in g/dm3

Respuesta :

helona

Answer:

i think so

Ba(OH)2 + H2SO4 ------> BaSO4 + 2H2O

1) Moles of Ba(OH)2 = moles of H2SO4 = 0.025L x 2)0.02M = 5.0 x 10^-4M

Concn of Ba(OH)2 in g/L = 5.0 x 10^-4M x 171.33g/mol = 0.086g/mol

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