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25.0cm3 of 0.020mol/dm3 sulphuric acid neutralises 18.6cm3 of barium hydroxide solution

1) find the concentration of the barium hydroxide solution in mol/dm3

2) find the concentration of the barium hydroxide solution in g/dm3

Respuesta :

Answer:

1) 0.027 mol/dm³

2)4.626 g/dm³

Explanation:

V(H2SO4)=25 cm³ =0.025dm³

c(H2SO4)=0.02 mol/dm³

V(Ba (OH)=18.5 cm³=0.0185dm³

1) V(Ba (OH)2)×c(Ba (OH)2=V(H2SO4)×c(H2SO4)

c(Ba (OH)2)=V(H2SO4)×c(H2SO4)/V(Ba (OH)2

c(Ba (OH)2)= 0.025dm³×0.02mol/dm³/0.0186dm³

c(Ba (OH)2)=0.027mol/dm³

2) γ(Ba (OH)2)=c(Ba (OH)2)×M(Ba (OH)2

γ(Ba (OH)2)=0.027mol/dm³×171,34 g/mol

γ(Ba (OH)2)=4.626g/dm³

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