How many grams of CuO would be required to produce 10.0 moles of
nitrogen gas in the following chemical reaction?
2 NH3(g) + 3 CuO(s) 3 Cu(s) + N2(g) + 3 H2O(g)

Respuesta :

Answer:

2390 CuO

Explanation:

                           2 NH3(g) + 3 CuO(s)  --->  3 Cu(s) + N2(g) + 3 H2O(g)

from reaction                         3 mol                               1 mol

given                                       x mol                               10.0 mol

x = 3*10.0/1 = 30.0 mol

M(CuO) = 63.5 + 16.0 = 79.5 g/mol

m(CuO) = 30.0 mol CuO * 79.5 gCuO/1 mol CuO = 2390 g CuO

                        2 NH3(g) + 3 CuO(s)  --->  3 Cu(s) + N2(g) + 3 H2O(g)

From reaction                        3 mol                               1 mol

Given                                     x mol                               10.0 mol

x = 3*10.0/1 = 30.0 mol

M(CuO) = 63.5 + 16.0 = 79.5 g/mol

m(CuO) = 30.0 mol CuO * 79.5 gCuO/1 mol CuO = 2390 g CuO

The answer is 2390 g CuO.

What is a chemical reaction and example?

A chemical reaction happens when one or more chemicals are changed into one or more other chemicals. Examples: iron and oxygen combining to make rust. vinegar and baking soda combine to make sodium acetate, carbon dioxide and water.

What are the 5 basic chemical reactions?

This becomes much easier for students to do when they learn the pattern of 5 basic categories of chemical reactions: synthesis, decomposition, single replacement, double replacement, and combustion.

Learn more about the chemical reactions here:  https://brainly.com/question/11231920

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