Answer: 6.0 g of silicon has more atoms
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]
a) [tex]\text{Number of moles of silicon}=\frac{6.0g}{28g/mol}=0.21moles[/tex]
1 mole of Si contains = [tex]6.023\times 10^{23}[/tex] atoms
0.21 moles of Si contains = [tex]\frac{6.023\times 10^{23}}{1}\times 0.21=1.26\times 10^{23}[/tex] atoms
b) [tex]\text{Number of moles of iron}=\frac{6.0g}{56g/mol}=0.11moles[/tex]
1 mole of Fe contains = [tex]6.023\times 10^{23}[/tex] atoms
0.11 moles of Fe contains = [tex]\frac{6.023\times 10^{23}}{1}\times 0.11=0.66\times 10^{23}[/tex] atoms
Thus 6.0 g of silicon has more atoms
