Answer:
39.1 °C
Explanation:
Recall the equation for specific heat:
[tex]q=mc \Delta T\\[/tex]
Where q is the heat, m is the mass, c is the specific heat of the substance (in this case water), and delta T is the change in temperature.
You should know that the specific heat of water is 1 cal/g/C.
Using the information in the question:
[tex]2035=500(1)(T-35)\\2035=500T-17500\\500T=19535\\T=39.07[/tex]
The final temperature is about 39.1 °C.
