Respuesta :

ni20479

Answer:

8w^2 I don't know why it is not on here, but I put it in an algebra calculator and everything. Good luck. :)

Step-by-step explanation:

Simply the radicals by multiplying and taking square roots.

2[tex]\sqrt[4]{8w^3}[/tex] * [tex]\sqrt[4]{32w^5}[/tex]

= 2[tex]\sqrt[4]{8w^3}[/tex] *2w[tex]\sqrt[4]{2w}[/tex]

= 4w[tex]\sqrt[4]{16w^4}[/tex]

=4w(2w)

=[tex]8w^{2}[/tex]

ItzMikeSS

Answer: Uhm... None of the options seem to be correct. The answer is: [tex]8w^2[/tex]

Step-by-step explanation:

[tex]2\sqrt[4]{8w^3}*\sqrt[4]{32w^5}[/tex]

This is the same as;

[tex]2\sqrt[4]{(8w^3)(32w^5)}[/tex]

[tex]2\sqrt[4]{256w^8}[/tex]

[tex]2\sqrt[4]{4^4w^8}[/tex]

[tex]2*4\sqrt[4]{w^8}\\ 8\sqrt[4]{w^8}\\8w^2[/tex]

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