Answer:
In 9.0 grams of water there are 0.11 mol of H₂.
Explanation:
The data we know is simple:
1 mole (H₂O) 18 g (H₂O)
- Taking this into account, a rule of 3 is made for 9.0 grams of water.
1 mole (H₂O) 18 g (H₂O)
X mole (H₂O) 9.0 g (H₂O)
- We clear the X =
X = 1 mol (H₂O) * 9 g (H₂O) / 18 g (H₂O)
X = 0.5 mol (H₂O)
- Now rule of 3 is done again but with the new data:
0.5 mol (H₂O) 9.0 g (H₂O)
X mol (H₂) 2 g (H) (Which is the same as H₂)
- Again we clear X:
X = 2 g (H) * 0.5 mol (H₂O) / 9.0 g (H₂O)
X = 0.11 gr (H₂)
