Step-by-step explanation:
Step 1: Use the quadratic formula to find the zeros
[tex]x=\frac{-b\pm \sqrt{b^2-4ac} }{2a}[/tex]
[tex]x=\frac{-(-16)\pm \sqrt{(-16)^2-4(8)(-15)} }{2(8)}[/tex]
[tex]x=\frac{16\pm \sqrt{736} }{16}[/tex]
[tex]x=\frac{16\pm 4\sqrt{46} }{16}[/tex]
[tex]x=\frac{4\pm \sqrt{46} }{4}[/tex]
Answer: [tex]x=\frac{4\pm \sqrt{46} }{4}[/tex]
