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A halloween assorted bag of candy contains 4 Snickers, 2 packages of M&M's, & 3 Butterfingers. What is the probability of selecting some M&M's, putting them back, and then selecting a Butterfinger? (DECIMAL FORM)

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JoyMark

Answer:

0.07

Step-by-step explanation:

First, add up all the numbers. This will be the denominator.

4+2+3=9

There are 9 pieces of candy.

Since you are randomly choosing two times you will have to multiply two fractions.

There are [tex]\frac{2}{9}[/tex] M&M's, and [tex]\frac{1}{3}[/tex] Butterfingers (You simplify)

Now you multiply these.

[tex]\frac{2}{9}[/tex]×[tex]\frac{1}{3}[/tex]=[tex]\frac{2}{27}[/tex]

Now make this into a decimal. To do this divide 2 and 27. which is approximately 0.07.

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