Sarah invests £2000 for 2 years in a saving account. She earns 3% per annum in compound interest. How much did Sarah have in her saving account after 2 years?

Respuesta :

Answer:

£2121.80

Step-by-step explanation:

The initial amount she invested is £2000. She invested for 2 years and at a rate of 3% compound interest.

The final amount she has after 2 years is given as:

[tex]A = P(1 +r)^t[/tex]

where P = principal (amount initially invested) = £2000

r = rate = 3%

t = number of years = 2 years

Hence, the final amount after 2 years is:

[tex]A = 2000(1 + \frac{3}{100})^2\\ \\A = 2000(1 + 0.03)^2\\\\A = 2000(1.03)^2 = 2000*1.0609[/tex]

A =  £2121.80

She will have £2121.80 in her savings account after 2 years.  

After 2 years Sarah 'account will have £ 2121.80.

Given that Sarah invests £ 2000 for 2 years in a saving account, and she earns 3% per annum in compound interest, to determine how much did Sarah have in her saving account after 2 years, the following calculation must be performed:

  • 2000 x 1.03 x 1.03 = X
  • 2000 x 1.0609 = X
  • 2121.80 = X

Therefore, after 2 years Sarah 'account will have £ 2121.80.

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