Answer: The [tex][H_3O^+][/tex] in a solution is [tex]4.0\times 10^{-13}[/tex]
Explanation:
pH or pOH is the measure of acidity or alkalinity of a solution.
pH is calculated by taking negative logarithm of hydrogen ion concentration.
To calculate the pOH of the solution, we use the equation:
[tex]pOH=-\log[OH^-][/tex]
We are given:
[tex]OH^-=2.5\times 10^{-2}[/tex]
Putting values in above equation, we get:
[tex]pOH=-\log[2.5\times 10^{-2}]=1.60[/tex]
[tex]pH+pOH=14[/tex]
[tex]pH=14-1.60=12.4[/tex]
[tex]12.4=-\log[H_3O^+][/tex]
[tex][H_3O^+]=4.0\times 10^{-13}[/tex]
The [tex][H_3O^+][/tex] in a solution is [tex]4.0\times 10^{-13}[/tex]
