Answer:
By AA property of similarity, triangles BAC and DFE are similar.
Step-by-step explanation:
Given information: AC║FE and AB║FD.
If a transversal line intersect two parallel lines, then the corresponding angles are equal.
In triangle BAC and triangle DFE
[tex]\angle ABC=\angle FDE[/tex] (corresponding angles)
[tex]\angle ACB=\angle FED[/tex] (corresponding angles)
Two corresponding angles of triangles are equal. So, by AA property of similarity both triangles BAC and DFE are similar.
[tex]\triangle BAC\sim \triangle DFE[/tex]
Hence proved.
