Respuesta :
Hello,
Number of solutions=3
x³-2x²-5x+6=x³-x²-x²+x-6x+6=x²(x-1)-x(x-1)-6(x-1)=(x-1)(x²-x-6)
=(x-1)(x²-3x+2x-6)=(x-1)(x(x-3)+2(x-3))
=(x-1)(x-3)(x+2)
Sol={1,3,-2}
Number of solutions=3
x³-2x²-5x+6=x³-x²-x²+x-6x+6=x²(x-1)-x(x-1)-6(x-1)=(x-1)(x²-x-6)
=(x-1)(x²-3x+2x-6)=(x-1)(x(x-3)+2(x-3))
=(x-1)(x-3)(x+2)
Sol={1,3,-2}
Answer:just took test
Step-by-step explanation:
x = 3, x = −1, x = 2