Respuesta :
n has oxidation number of +2; each O has an oxidation number of -2; each H has an oxidation number of +1, leaving you with an overall net charge of -2
Zn(OH)4= ; -2 = -4 + ?, Zn = +2 , the -4 is the charge on the 4 OH- ions
Zn(OH)4= ; -2 = -4 + ?, Zn = +2 , the -4 is the charge on the 4 OH- ions
Answer:
The oxidation number for Zn = +2 and OH- = -1
Explanation:
Given:
Transition metal complex with the formula [tex][Zn(OH)_{4}]^{2-}[/tex]
To determine:
The oxidation state of Zn
Explanation:
The given complex is a negatively charged ion with a net charge of -2.
The hydroxyl ion (OH) is associated with an oxidation number of -1.
If 'x' is the oxidation number for Zn, then the sum of the charges is equal to the net charge on the ion
[tex]x + 4(-1) = -2\\\\x = -2+4 = +2[/tex]