Answer:
- -1,42x10³ J
- -2,23x10³ J
Explanation:
When a gas expands it produce energy as work. The equation that explain this phenomenon is:
Work (w) = - External pressure × ΔV
In the first question. We have an external pressure of 1,00 atm and the ΔV is:
1,00 L - 15,0 L = 14 L
Thus, in this case work is:
w = - 1,00 atm × 14,0 L = -14,0 atm·L
The problem does not especify the units to solve this problem, for international system of units (SI) Joules is the correct unit for energy, so:
-14,0 atm·L ×(101,325 J / 1 atm·L) = -1,42x10³ J
In the second problem occurs the same principle but occurs in two steps. The work done in the first step is:
w = - 5,00 atm × (3,00 L - 1,00 L) = -10 atm·L ×(101,325 J / 1 atm·L) =
-1,01x10³ J
In second step:, the work is:
w = - 1,00 atm × (15,0 L - 3,00 L) = -12 atm·L ×(101,325 J / 1 atm·L) =
-1,22x10³ J
Thus, the work done in the process is:
w = -1,01x10³ J - 1,22x10³ J = -2,23 x10³ J
I hope it helps!
