Respuesta :

we know that

A perfect cube is a whole number which is the cube of another whole number or a number is a perfect cube if the cube root of that number is a whole number.

so

case a) [tex] 12x^{12} y^{18}[/tex]

[tex] 12x^{12} y^{18} = 12(x^{4} y^{6})^{3}[/tex]

the cube root of [tex] 12 [/tex] is not a whole number

therefore

The expression is not a perfect cube

case b) [tex] 12x^{27} y^{125}[/tex]

[tex] 12x^{27} y^{125} = 12(x^{9})^{3}y^{125} [/tex]

the cube root of [tex] 12 [/tex] is not a whole number

the cube root of [tex] y^{125} [/tex] is not a whole number

therefore

The expression is not a perfect cube

case c) [tex] 64x^{15} y^{18}[/tex]

[tex] 64x^{15} y^{18} = (4 x^{5} y^{6})^{3}[/tex]

therefore

The expression is a perfect cube

case d) [tex] 64x^{27} y^{125}[/tex]

[tex] 64x^{27} y^{125} = (4 x^{9})^{3}y^{125}[/tex]

the cube root of [tex] y^{125} [/tex] is not a whole number

therefore

The expression is not a perfect cube

the answer is

[tex] 64x^{15} y^{18}[/tex]

Answer: C

Step-by-step explanation:

yes

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