Chords and intersect in circle O as shown in the diagram. Two of the angle measurements are marked. What is mCED?
we know that
The measure of the interior angle is the half sum of the arcs comprising it and its opposite
so
m∠CED=[tex] \frac{1}{2} *(arc\ AB+arc\ CD) [/tex]
see the attached figure with letters to better understand the problem
[tex] arc\ AB=82 [/tex]° ------> by central angle
[tex] arc\ CD=48 [/tex]° ------> by central angle
Substitute the values in the formula above
m∠CED=[tex] \frac{1}{2} *(82+48) [/tex]
m∠CED=[tex] \frac{1}{2} *130 [/tex]
m∠CED=[tex] 65 [/tex]°
therefore
the answer is
m∠CED=[tex] 65 [/tex]°