Answer:
7.5g
Explanation:
Given parameters:
Mass of gallium = 5.3g
Mass of oxygen = 5.3g
Unknown:
Mass of gallium oxide produced = ?
Solution:
To solve this problem, let us write the reaction equation:
Gallium reacts with oxygen to produce gallium oxide
4Ga + 3O₂ → 2Ga₂O₃
Let us determine the limiting reactant from the equation. This reactant is the one in short supply and it determines the extent of the reaction.
Number of moles = [tex]\frac{mass}{molar mass}[/tex]
Number of moles of Ga = [tex]\frac{5.3}{69.7}[/tex] = 0.08mole
Number of moles of O₂ = [tex]\frac{5.3}{32}[/tex] = 0.17mole
From the balance reaction equation;
4 moles of Ga reacted with 3 moles of O₂
0.08 moles of Ga will require [tex]\frac{0.08 x 3}{4}[/tex] = 0.06 moles of O₂
But we were given 0.17 moles. This implies that oxygen gas is in excess
If :
4 moles of Ga gives 2 moles of Ga₂O₃
0.08 moles of Ga will produce [tex]\frac{0.08 x 2}{4}[/tex] = 0.04moles
Mass of Ga₂O₃ = number of moles x molar mass
Molar mass of Ga₂O₃ = 2(69.7) + 3(16) = 187.4g/mol
Mass of Ga₂O₃ = 0.04 x 187.4 = 7.5g
