25 g of NH₃ will produce 47.8 g of (NH₄)₂S
Explanation:
2 NH₃ + H₂S ----> (NH₄)₂S
Molecular weight of NH₃ = 17 g/mol
Molecular weight of (NH₄)₂S = 68 g/mol
According to the balanced reaction:
2 X 17 g of NH₃ produces 68 g of (NH₄)₂S
1 g of NH₃ will produce [tex]\frac{68}{34}[/tex] g of (NH₄)₂S
25g of NH₃ will produce [tex]\frac{65}{34} X 25 g[/tex] of (NH₄)₂S
= 47.8 g of (NH₄)₂S
Therefore, 25 g of NH₃ will produce 47.8 g of (NH₄)₂S
