Answer:
11.37 lb-ft
Step-by-step explanation:
We are given that
Force,F=3 pounds
[tex]\theta=42^{\circ}[/tex]
Let Point A (3,7) and point B(8,8)
We have to find the work done by the force.
[tex]d=<(8-3)+(8-7)>=<5,1>[/tex]
[tex]r=\mid d\mid=\sqrt{x^2+y^2}=\sqrt{5^2+1^2}=\sqrt{26}[/tex] feet
We know that Work done by the force
[tex]W=Frcos\theta[/tex]
Substitute the values
[tex]W=3\times \sqrt{26}cos42=11.37 lb-ft[/tex]
Hence, the work done by the force =11.37 lb-ft
