The volume of a can varies jointly as the height of the can and the square of the radius. A can with an 8 inch height and 4 inch radius has a volume of 402.12 inches cubed. What is the volume of a can that has a 2 inch radius and a 10 inch height

Respuesta :

Answer:

Therefore the volume of the can is 1256.625 inches cubes.

Step-by-step explanation:

The volume of can directly proportional to the height of the can and the square of the radius.

[tex]V\propto hr^2[/tex]

V= The volume of the can

h= Height of the can

r= radius of the can.

[tex]\therefore \frac{V_1}{V_2}=\frac{h_1r_1^2}{h_2r_2^2}[/tex]

Here [tex]V_1=[/tex] 402.12 inches cubes, [tex]h_1=[/tex] 8 inch, [tex]r_1=[/tex] 4 inch, [tex]h_2=[/tex] 10 inch, [tex]r_2=[/tex] 2 inch, [tex]V_2=?[/tex]

[tex]\therefore \frac{V_1}{V_2}=\frac{h_1r_1^2}{h_2r_2^2}[/tex]

[tex]\Rightarrow \frac{402.12}{V_2}=\frac{8\times 4^2}{10\times 2^2}[/tex]

[tex]\Rightarrow \frac{V_2}{402.12}=\frac{10\times 2^2}{8\times 4^2}[/tex]

[tex]\Rightarrow {V_2}=\frac{10\times 2^2}{8\times 4^2}\times {402.12}[/tex]

[tex]\Rightarrow V_2=1256.625[/tex] inches cubes

Therefore the volume of the can that has 2 inch radius and 10 inch height is 1256.625 inches cubes.

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