Respuesta :
The length of the carpet is 10 feet and the width of the carpet is 15 feet
Explanation:
Given:
Area of the carpet, A = 150 ft²
Let x be the length of the carpet
Let y be the width of the carpet
According to the question:
width, y = 2x - 5 -1
We know:
Area of rectangle = length X width
On substituting the value we get:
150 = (x) (2x - 5)
150 = 2x² - 5x
2x² - 5x - 150 = 0
Solving the quadratic equation we get
x = 10 feet
Substituting x = 10 ft in equation 1 we get:
y = 2x - 5
y = 2(10) - 5
y = 15 feet
Therefore, the length of the carpet is 10 feet and the width of the carpet is 15 feet
The length and with of the carport are 10 ft and 15 ft respectively.
Area of the rectangular carport = 150 ft²
let
l = length
width = w = 2l - 5
The length and width can be found below
area = 150 ft²
area = lw
150 = l(2l - 5)
150 = 2l² - 5l
2l² - 5l - 150 = 0
using quadratic formula,
2l² - 5l - 150 = 0
- b±√b² - 4ac / 2a
where
a = 2
b = -5
c = -150
5±√25 + 1200 / 4
5 ± √1225 / 4
5 ± 35 / 4
Therefore,
l = 10 or - 15 / 2
The length can only be positive
so, l = 10 ft
150 = lw
w = 150 / 10
width = 15 ft
read more: https://brainly.com/question/23063829?referrer=searchResults
