Answer:
The answer to your question is 1.8 %
Explanation:
Data
mass of Li = 15.3 g
mass of Cu = 1.25 g
Percent yield = ?
-Balanced chemical reaction
6Li + Cu₃(PO₄)₂ ⇒ 2Li₃PO₄ + 3Cu
-Calculate the theoretical yield of Cu
molar mass of Li = 6 x 6.94 = 41.64 g
molar mass of Cu = 3(63.55) = 190.65 g
41.64 g of Li --------------- 190.65 g of Cu
15.3 g of Li ---------------- x
x = (15.3 x 190.65) / 41.64
x = 70.05 g of Cu
-Calculate the percent yield
Percent yield = 1.25/70.05 x 100
= 1.8 %
