Answer:
The answer to your question is C₁.₄H₁
Explanation:
Data
Percent of H = 5.611%
Percent of C = 100 - 5.611
= 94.389 %
Empirical formula = ?
Process
1.- Express the percents as mass
Hydrogen = 5.611 g
Carbon = 94.389 g
2.- Convert the grams to moles
Hydrogen
1 g ----------------- 1 mol
5.611 g -------------- x
x = (5.611 x 1) / 1
x = 5.611 moles
Carbon
12 g ------------------- 1 mol
94.389 g ------------ x
x = (94.389 x 1) / 12
x = 7.866 moles
3.- Divide by the lowest number of moles
Hydrogen 5.611 / 5.611 = 1
Carbon 7.866 / 5.611 = 1.4
4.- Write the empirical formula
C₁.₄H₁
