Answer:
The answer to your question is 98.9 %
Explanation:
Data
moles of methane = CH₄ = 2.0
excess air
Percent yield = ?
mass of CO₂ = 87 g
- Balanced chemical reaction
CH₄ + 2O₂ ⇒ CO₂ + 2H₂O
Reactants Elements Products
1 C 1
4 H 2
4 O 2
- Calculate the molar mass of CH₄
CH₄ = 12 + 4 = 16 g
- Convert the moles to mass
16 g of CH₄ ----------------- 1 mol
x ----------------- 2 moles
x = (2 x 16) / 1
x = 32 g of CH₄
-Calculate the theoretical formation of CO₂
16 g of CH₄ ----------------- 44 g of CO₂
32 g of CH₄ ---------------- x
x = (32 x 44) / 16
x = 88 g of CO₂
-Calculate the Percent yield
Percent yield = Actual yield/Theoretical yield x 100
Percent yield = 87/88 x 100
Percent yield = 98.9 %
