contestada

the horizontal distance x traveled by a soccer ball if it is kicked from ground level with an initial velocity of v at angle theta is x=1/32(vsquared) sin2theta. Which of the following is an equivalent expression for x?
a. 1/16(vsquared) sintheta
b.1/32(vsquared) cos2theta
c.1/32(vsquared) sinthetacostheta
d.1/16(vsquared) sinthetacostheta

Respuesta :

sqdancefan

Answer:

  d. 1/16v²sin(θ)cos(θ)

Step-by-step explanation:

The relevant trig identity is ...

  sin(2θ) = 2sin(θ)cos(θ)

Substituting this into the given expression gives ...

  x = 1/32v²sin(2θ) = (1/32v²)(2v²sin(θ)cos(θ))

  x = 1/16v²sin(θ)cos(θ)

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