The pressure the gas exerts at a new temperature is required.
The pressure at the required temperature is 0.695 atm.
Gas laws
[tex]P_1[/tex] = Initial pressure = 0.600 atm
[tex]T_1[/tex] = Initial temperature = 25.2°C = 25.2+273.15 = 298.35 K
[tex]T_2[/tex] = Final temperature = 72.4°C = 72.4+273.15 = 345.55 K
[tex]P_2[/tex] = Final pressure
As volume and number of moles is constant we have the relation
[tex]\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}\\\Rightarrow P_2=\dfrac{P_1}{T_1}\times T_2\\\Rightarrow P_2=\dfrac{0.6}{298.35}\times 345.55\\\Rightarrow P_2=0.695\ \text{atm}[/tex]
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