The work done in lifting the weight on an inclined plane is 2598N
Explanation:
Given:
Weight, W = 500N
Distance, s = 6m
[tex]sin \alpha = \frac{Perpendicular}{hypotenuse}[/tex]
Where,
Perpendicular = 3m
Hypotenuse = 6m
Substituting the value:
[tex]sin \alpha = \frac{3}{6} \\\\sin \alpha = \frac{1}{2} \\\\\alpha = 30^o[/tex]
Work done = F X scosα
[tex]W = 500 X 6 X cos(30)\\\\W = 3000 X \frac{\sqrt{3} }{2} \\\\\\W = 1500\sqrt{3} \\\\W = 2598N[/tex]
Therefore, work done in lifting the weight on an inclined plane is 2598N
