Can someone please help? I'm too dumbo to answer this on my own.
Answer:
d. [tex]\sqrt{3V\pi h }[/tex]/πh
Step-by-step explanation:
isolating r
3* V = 3 * [tex]\frac{1}{3} \pi r^2h[/tex]
3V = [tex]\pi r^2h[/tex]
[tex]\frac{\pi r^2h}{\pi h} = \frac{3V}{\pi h}[/tex]
[tex]r^2 = \frac{3V}{\pi h}[/tex]
[tex]\sqrt{r^2}= \sqrt{\frac{3V}{\pi h} }[/tex]
r = [tex]\sqrt{\frac{3V}{\pi h} }[/tex] = [tex]\sqrt{\frac{3V}{\pi h} }* \frac{\sqrt{\pi h} }{\sqrt{\pi h} }[/tex]= [tex]\frac{\sqrt{3V\pi h }}{\pi h}[/tex]