Please help, i cant find any good answers for this one.
Use the quadratic formula to find the exact solutions of x2 − 5x − 2 = 0.
x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a

x equals 5 plus or minus the square root of 33, all over 2
x equals negative 5 plus or minus the square root of 33, all over 2
x equals 5 plus or minus the square root of 17, all over 2
x equals negative 5 plus or minus the square root of 17, all over 2

Respuesta :

Answer:

a. x equals 5 plus or minus the square root of 33, all over 2

Step-by-step explanation:

x = (5 +- √25+8)/2 = (5 +- √33)/2

sounds like x equals 5 plus or minus the square root of 33, all over 2 to me

A quadratic equation has a leading coefficient of the second degree. The value of x equals negative 5 plus or minus the square root of 33, all over 2.

What is a quadratic equation?

A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers.

It is written in the form of ax²+bx+c.

A quadratic equation is can be solved using the formula,

[tex]\text{Roots of quadratic equation} = \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

where a, b, and c is the coefficient of x², coefficient of x, and constant respectively. Now, if we describe the value of a, b, and c for the equation x²-5x-2=0, then the value will be a is 1, b is -5, and c is -2. Therefore, the root of the equation can be written as,

[tex]\text{Roots of quadratic equation}, x = \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

                                             [tex]=\dfrac{-(-5)\pm \sqrt{(-5)^2-(4\times 1 \times -2)}}{2 \times 1}\\\\=\dfrac{5\pm \sqrt{25+8}}{2}\\\\=\dfrac{5\pm \sqrt{33}}{2}[/tex]

Thus, the value of x can be written as equal negative 5 plus or minus the square root of 33, all over 2.

Learn more about Quadratic Equations:

https://brainly.com/question/2263981

Q&A Education