Known :
r = 5
θ = 180°
Asked :
Arc length of the semicircle = ...?
Answer :
Arc length
[tex] = \frac{θ}{360} \times 2\pi r \\ = \frac{180}{360} \times 2 \times 3.14 \times 5 \\ = \frac{1}{2} \times 31.4 \\ = \frac{1}{2} \times \frac{314}{10} \\ = \frac{314}{20} \\ = 15.7[/tex]
So, the arc length of the semicircle is 15,7 units
Hope it helps and is useful :)
