Answer:
The correct answer is option c.
Explanation:
[tex]E=h\nu =\frac{h\times c}{\lambda}[/tex]
where,
E = energy of photon = ?
h = Planck's constant = [tex]6.63\times 10^{-34}Js[/tex]
[tex]\nu [/tex] =- frequency of the wave
c = speed of light = [tex]3\times 10^8m/s[/tex]
[tex]\lambda[/tex] = wavelength of the radio wave photon
Now put all the given values in the above formula, we get the energy of the photons.
[tex]E=6.63\times 10^{-34}Js\times 1.255\times 10^6 s^{-1}[/tex]
[tex]E=8.316\times 10^{-28}J[/tex]
Hence, the correct answer is option c.
