Answer:
[tex]Sine \ B\approx 0.95[/tex]
Step-by-step explanation:
-We use the Law of Sines to find the Sine of ∠B.
-We notice that ∠B corresponds to length DC=35.
#We therefore calculate the Sine of ∠B as follows:
[tex]\frac{a}{Sin \ A}=\frac{b}{Sin \ B}\\\\\frac{37}{Sin \ 90\textdegree}=\frac{35}{Sin \ B}\\\\=>Sin \ 90\textdegree=1\\\\\therefore Sin \ B=\frac{35}{37}\\\\=0.9459\approx0.95[/tex]
Hence, the Sine of ∠B is approximately 0.95
