A chemist dissolves 73 grams of sodium chloride (NaCl) in water, final volume is 1,050mL then molarity of solution is 1.18M.
How do we calculate molarity?
Molarity of any solution is define as the number of moles of solute present in per liter of the solution & it is represented as:
M = n/V
And moles will be calculated as:
n = W/M, where
W = given mass of NaCl = 73 grams
M = molar mass of NaCl = 58.44 g/mol
So, n = 73/58.44 = 1.24 moles
Given volume of solution = 1,050mL = 1.05L
On putting values on first equation, we get
M = 1.24/1.05 = 1.18 M
Hence required molarity of NaCl is 1.18M.
To know more about molarity, visit the below link:
https://brainly.com/question/26528084
