Answer:
[tex]P(3,red \ and\ 3, blue)=\frac{1}{36}[/tex]
Step-by-step explanation:
-A fair die has 6 faces, a sample space of 6 and each space has a probability of 1/6:
#The probability of 3 in the red die;
[tex]P(3,red)=\frac{1}{6}[/tex]
#The probability of 3 in blue die:
[tex]P(3,blue)=\frac{1}{6}[/tex]
The probability of a 3 in both dice is the product of the individual probabilities:
[tex]P(3,red and 3, blue)=P(3,red)\times P(3,blue)\\\\=\frac{1}{6}\times \frac{1}{6}\\\\=\frac{1}{36}[/tex]
Hence, the probability of a 3 in both dice is [tex]\frac{1}{36}[/tex]
