Respuesta :

The sum of the given sequence is -6384.

Step-by-step explanation:

The given Arithmetic sequence is 14 + 8 + 2+ ... + ( 274) + (-280).

  • The first term of the sequence = 14
  • The last term of the sequence = -280
  • The common difference ⇒ 14 - 8 = 6

To find the number of terms in the sequence :

The formula used is [tex]n = (\frac{a_{n}-a_{1}} {d})+1[/tex]

where,

  • n is the number of terms.
  • [tex]a_{n}[/tex] is the late term which is -280.
  • [tex]a_{1}[/tex] is the first term which is 14.
  • d is the common difference which is 6.

Therefore, [tex]n =(\frac{-280-14}{6}) +1[/tex]

⇒ [tex]n =( \frac{-294}{6}) + 1[/tex]

⇒ [tex]n = -49 + 1[/tex]

⇒ [tex]n = -48[/tex]

⇒ n = 48, since n cannot be negative.

∴ The number of terms, n = 48.

To find the sum of the arithmetic progression :

The formula used is [tex]S = \frac{n}{2}(a_{1} + a_{n} )[/tex]

where,

  • S is the sum of the sequence.
  • [tex]a_{1}[/tex] is the first term which is 14.
  • [tex]a_{n}[/tex] is the late term which is -280.

Therefore, [tex]S = \frac{48}{2}(14+ (-280))[/tex]

⇒ [tex]S = \frac{48}{2}(-266)[/tex]

⇒ [tex]S = 48 \times -133[/tex]

⇒ [tex]S = -6384[/tex]

∴ The sum of the given sequence is -6384.

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