Answer:
[tex]\huge\boxed{5z^2+19z-4=(z+4)(5z-1)}[/tex]
Step-by-step explanation:
[tex]5z^2+19z-4=5z^2+20z-z-4\\\\\qquad\text{use the distributive property}:a(b+c)=ab+ac\\\\=5z(z+4)-1(z+4)\\\\\qquad\text{use the distributive property}:a(b+c)=ab+ac\\\\=5z\underbrace{(z+4)}_{a}-1\underbrace{(z+4)}_{a}=(z+4)(5z-1)[/tex]
