Answer:
[tex]-9(\frac{2}{3}x) + 9(1)\\ \\-6x + 9[/tex]
Explanation:
Before we begin, remember the following rules:
1- Distribution property:
[tex]a(b+c) = ab+ac[/tex]
2- Simplification of fractions:
[tex]\frac{xy}{yz}=\frac{x}{z}[/tex]
3- Signs in multiplication:
+ve * +ve = +ve
-ve * -ve = +ve
+ve * -ve = -ve
Now, for the given problem, we have:
[tex]9 (\frac{2}{3}x + 1)[/tex]
Starting with the distributive property:
[tex]-9 (\frac{2}{3}x +1) = -9(\frac{2}{3}x) - (-9)(1) = -9(\frac{2}{3}x) + 9(1)[/tex]
..................>This corresponds to option 1
Now, we simplify the output from the above step:
[tex]-9(\frac{2}{3}x) + 9 = \frac{-9*2}{3}x + 9 = -6x+9[/tex]
................> This corresponds to option 5
Hope this helps :)
