Answer:
Mass of C needed =59.4 g
Explanation:
Given data:
Mass of C needed = ?
Mass of Fe₂O₃ = 525 g
Solution:
Balance chemical equation:
2Fe₂O₃ + 3C → 4Fe+ 3CO₂
Number of moles of Fe₂O₃:
Number of moles = mass/ molar mass
Number of moles = 525 g/ 159.69 g/mol
Number of moles = 3.3 mol
Now we will compare the moles of Fe₂O₃ with carbon from balance chemical equation.
Fe₂O₃ : C
2 : 3
3.3 : 3/2×3.3 = 4.95 mol
Mass of carbon:
Mass = number of moles × molar mass
Mass = 4.95 mol × 12 g/mol
Mass = 59.4 g
