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If you wanted to make 0.800 Liters of a 0.531 M solution of Nickel(II) chloride, NiCl2, how many grams of NiCIZ
would you need? Use the unit canceling method to determine the grams of NiCl2
Molar mass= 129g/mol. Moles = 0.4248
.

If you wanted to make 0800 Liters of a 0531 M solution of NickelII chloride NiCl2 how many grams of NiCIZ would you need Use the unit canceling method to determ class=

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Answer:

  • 54.8g

Explanation:

1. Calculate the number of moles of NiCl₂

a) Identify the known variables

  • V =0.800 liters
  • M = 0.531M
  • n = ?

b) Formula

       [tex]M=\dfrac{n}{V}[/tex]

c) Clear n

        [tex]n=M\times V[/tex]

g) Substitute and compute

         [tex]n=0.531M/times 0.800liters=0.4248mol[/tex]

2. Convert moles to grams

a) molar mass of NiCl₂

  • 129g/mol (shown in the problem)

b) Unit canceling method

Use the factors in order to cancel the units to obtain grams

      [tex]0.4248mol\times 129\dfrac{g}{mol}=54.7992g[/tex]

Note that the mol unit appears on the numerator and denominator, so it cancels leaving just g (grams).

c) Round to 3 signficant figures

     [tex]54.8g[/tex]

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