In a certain Algebra 2 class of 21 students, 6 of them play basketball and 14 of them play baseball. There are 5 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

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bsong3810 bsong3810 · Answer 1 · 2020-04-05T15:00:45+02:00

Answer:

Step-by-step explanation:

5 of them play neither sport.

We can subtract 5 from 21 to get the kids that play a sport.

16-(14+6), is -4.

so 4 is the number of kids that play both sports.

so the probability is 4/21.

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abidemiokin abidemiokin · Answer 2 · 2021-12-09T12:13:58+01:00

The probability that a student is chosen randomly from the class plays both basketball and baseball is 4/21

Probability is the likelihood or chance that an event will occur.

If the total number of people in the class is 21 students, hence the total outcome is 21

Get the number of students that plays both basketball and baseball

n(U) = n(B)only + n(Ba)only + n(BnBa) + n(BuBa)'

21 = 6-x + 14-x + x + 5

21 = 25 -x

x = 25 - 21

x = 4

Hence 4 students play both basketball and baseball

Pr(basketball and baseball) = 4/21

Hence the probability that a student chosen randomly from the class plays both basketball and baseball is 4/21

Learn more on probability here; https://brainly.com/question/13604758