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In a recent​ poll, 44​% of survey respondents said​ that, if they only had one​ child, they would prefer the child to be a boy. Suppose you conducted a survey of 150 randomly selected students on your campus and find that 71 of them would prefer a boy.
​(a) Use the normal approximation to the binomial to approximate the probability​ that, in a random sample of 150 ​students, at least 71 would prefer a​ boy, assuming the true percentage is 44​%.
​(b) Does this result contradict the​ poll? Explain.

Respuesta :

abiolatolu90

Answer:

a) The probability that 71 of 150 will prefer boy child is 71/150 or 0.47

b) The result contradicts the poll actual percentage is 47.33% which is 3.33% more than the poll predicted

Step-by-step explanation:

If 71 out of 150 prefer boy child

The probability that the 71 will prefer boy child is

= 71/150

The actual percentage is

(71/150)*100%

= 47.33%

This contradicts the poll as this is more than the poll predicted. That means Less than 71 of 150 actually preferred boy child.

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