If the height is 9 units and the volume is 36 cubic units, what is the surface area of a right circular cylinder?
Volume
36π = πr^2*(9) ; Divide both sides by π and 9
4 = r^2 ; Take the square root of both sides
2 = r
Surface area
= 2π(2)(9) + 2π(2)^2
= 4π(9) + 2π(4)
= 36π + 8π
= 44π
Answer:
44π square units.
Step-by-step explanation:
The volume
36 = π r^2 h
36 = 9π r^2
π r^2 = 36/9 = 4π ( = the area of the base).
Now r^2 = 4
and r = 2.
So the circumference of the base = 2 * π * 2.
= 4π.
The area of the curve surface = 9 * 4π
= 36π.
The surface are of the cylinder = 2 * area of the base + area of the curved surface
= 2 * 4π + 36π
= 44π square units.